Algebra homework help?

Thank you to everyone who helped me! (Abstract, Makkine, RiceCake, and Spyder)
Gonna make another thread whenever I need more help lol, or maybe post here.

......

I wish I could help, but I'm in 7th grade. I'm not that advanced in algebra, even though I have a 96% in math.

I pm'd you what you need to do.

I'm also a ninth grader, but I'm doing Geometry, not Algebra II. I'll help from what I can remember from last year

A. y-4x=-3

B. 3y-3x=9

C. 3x+2y=12

D. 2(x-3)+3y=0

Okay, so all you have to do here is identify where the y is, and then use the additive property of equality to turn the equation into y = mx + b format. I'll walk you through the first and last one, but I think you'll understand B and C.
A. y-4x=-3
So, all you have to do is take the x to the other side, right? You do this by cancelling out x. Since -4x is negative, all you have to do is add 4x. But! Whatever you do to one side, you have to do to the other. So add a 4x to -3, too.
A. y-4x+4x=-3+4x
A. y=-3+4x
And there you have it! You can switch around the products, too, to get y=4x-3. y=mx+b, see?


D. 2(x-3)+3y=0
D is a little tricky because you have to simplify first. So, multiply 2 by everything inside the parentheses.
D. 2x-6+3y=0
Send the 6 to the other side.
D. 2x-6+6+3y=0+6
D. 2x+3y=6
Send 2x to the other side
D. 2x-2x+3y=6-2x
D. 3y=6-2x
BUT WAIT! You need to leave y completely alone, which you can do using the multiplicative property of equality! (the same thing as the additive property, just use division and multiplication)
D. 3y/3=6/3-2x/3
D. y=2-2/3x
Ta-da!

Im gonna write it step by step:

Problem A:
1. y-4x=-3
2. y-4x+4x=-3+4x
3. y=-3+4x
4. y=4x-3

Problem B:
1. 3y-3x=9
2. 3y-3x+3x=9+3x
3. 3y=9+3x
4. 3y/3=(9+3x)/3
5. y=3+x
6. y=x+3

Problem C:
1. 3x+2y=12
2. 3x-3x+2y=12-3x
3. 2y=12-3x
4. 2y/2=(12-3x)/2
5. y=6-3/2x
6. y=-3/2x+6

Problem D:
1. 2(x-3)+3y=0
2. 2x-6+3y=0
3. 2x-2x-6+3y=0-2x
4. -6+3y=-2x
5. -6+6+3y=-2x+6
6. 3y=-2x+6
7. 3y/3=(-2x+6)/3
8. y=-2/3x+2

I hoped this helps!

I'm in Algebra 2 Scholars so I know how to do this stuff.
What you want to do is isolate y. Just remember that when you move things across the equal sign, the number's sign has to chance. So to do A would look like this:

y-4x=-3

Add 4x to the other side in y=mx+b format

y=4x+(-3)

For B, you would do the exact same thing, except you'd have to divide all the numbers on the left side of the equal's sign by 3. Hope I helped.

And you know how to graph right?


EDIT: Lol, ninja'd

EDIT x2: twice

Oh em gee thank you guys! I only need one more thing and I will be done

Question A: (2x² + 3x +5)+(x² + 2x +8 )
Answer: 3x²+5x+13

Question B: (3x² + 8x + 1)+(2x² + 8x + 4 )
Answer: 5x²+16x+5

Question C: (3x² + 5x + 7)-(4x² + x + 1 )
Answer: -x²+4x+6

Question D: C. (3x² + 5x + 7)-(4x² + x + 1 )
Answer: 5x

Basically, all u do is what the operation between the 2 parenthese says. For example, questions a and b have an addition symbol, which means ur gonna add. Questions c and d have a minus symbol, which means ur gonna subtract. The pluses and minuses in the parenthese are just telling u if its positive or negative.

Hope this helped!